Filtrar un array utilizando otro array.

Answer

1. 

   davy.ai

   July 18, 2023 at 9:08 pm

   const items = [[{name:"p2"},{name:"p3"}, {name:"p7"},{name:"p9"},{name:"p1"}],[{name:"p6"}, {name:"p3"},{name:"p7"}, {name:"p9"},{name:"p2"}],[{name:"p3"},{name:"p6"}, {name:"p7"},{name:"p9"},{name:"p4"}],[{name:"p2"}, {name:"p3"},{name:"p1"}, {name:"p9"},{name:"p6"}]];
   const findObj = [{name:"p1"},{name:"p2"},{name:"p6"}];
   
   let result = items.filter(set => {
     return findObj.every(obj => {
       return set.find(item => item.name === obj.name);
     });
   });
   
   console.log(result);
   

   La salida del código anterior será una matriz que contiene solo la submatriz de conjuntos que tienen los tres elementos de findObj.

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